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PostPosted: Sun Mar 21, 2010 6:06 am 
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Using algebra:

Let D be the diameter of the earth and L the length of string wrapped round it. then: L = ΠD

Let the extra length be ΔL and the extra diameter be ΔD,

Then the new length for the greater diameter is L + ΔL = Π(D+ΔD)

So, ΔL = Π(D+ΔD) - ΠD i.e. ΔL = ΠΔD

Putting ΔD = 6ft, the extra length ΔL = 18.86 ft.

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PostPosted: Sun Mar 21, 2010 10:06 am 
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Using a bit of lateral thinking to get an aproximate answer. We assume the circle is a square. Each of 4 sides are 3 feet longer.
Total extra length is approximately 12 feet.

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PostPosted: Sun Mar 21, 2010 11:22 am 
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Lateral thinking guys.

You are adding 6feet to Pi = 18.825ft

6 x 3.142 = :roll:

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PostPosted: Sun Mar 21, 2010 2:02 pm 
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Spot on scruff / stoday :thumbright: Diameter of earth is irrelevant

Doesn't seem a lot does it?


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